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Poles to have Different Temperature (Ref: Axial Tilt suggestion) (#964)

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* Initial Idea

* Changed Names:
Currently still only on NorthTemperature reliant, compadible version

* Restored Generation of Temperature

* Temperature Function found

* Version Bump

* Scuffed Saving solution

* Current Version(without the save changes)

* Globe Temperature Display

* Individual Regeneration of Temperatures

* Fixed Loading and Saving
New Maps save a Dummy 0 at settings[17]

* Final Version Bump
(currently no description for the Update)

---------

Co-authored-by: Azgaar <maxganiev@yandex.com>
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Leo 2023-08-05 08:29:49 +02:00 • committed by GitHub
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commit efdcaf7db3
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9 changed files with 61 additions and 32 deletions
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16
main.js
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@ -184,6 +184,8 @@ let options = {
pinNotes: false,
showMFCGMap: true,
winds: [225, 45, 225, 315, 135, 315],
tempNorthPole: 0,
tempSouthPole: 0,
stateLabelsMode: "auto"
};
let mapCoordinates = {}; // map coordinates on globe
@ -1008,16 +1010,20 @@ function calculateTemperatures() {
TIME && console.time("calculateTemperatures");
const cells = grid.cells;
cells.temp = new Int8Array(cells.i.length); // temperature array
const tEq = +temperatureEquatorInput.value;
const tPole = +temperaturePoleInput.value;
const tDelta = tEq - tPole;
const tNorthPole = +temperatureNorthPoleInput.value;
const tSouthPole = +temperatureSouthPoleInput.value;
//Update Settings to match the slider(there may be a better solution)
options.tempSouthPole = +tSouthPole;
options.tempNorthPole = +tNorthPole;
const tNDelta = tEq - tNorthPole;
const tSDelta = tEq - tSouthPole;
const int = d3.easePolyInOut.exponent(0.5); // interpolation function
d3.range(0, cells.i.length, grid.cellsX).forEach(function (r) {
const y = grid.points[r][1];
const lat = Math.abs(mapCoordinates.latN - (y / graphHeight) * mapCoordinates.latT); // [0; 90]
const initTemp = tEq - int(lat / 90) * tDelta;
const lat = (mapCoordinates.latN - (y / graphHeight) * mapCoordinates.latT); // [-90; 90]
const initTemp = tEq - (Math.max(rn(lat / 90, 2), 0) * tNDelta - Math.min(rn(lat / 90, 2), 0) * tSDelta);
for (let i = r; i < r + grid.cellsX; i++) {
cells.temp[i] = minmax(initTemp - convertToFriendly(cells.h[i]), -128, 127);
}